概述
a = np.array([[1,2,3,4,5,6],[7,8,9,10,11,12],[3,6,7,9]])
我想对第一行的前两个值求和：1 2 = 3,然后是下两个值：3 4 = 7,然后5 6 = 11,依此类推每一行.我想要的输出是这样的：
array([[ 3,11],[15,19,23],[ 8,13,17]])
def sum_chunks(x,chunk_size):
rows,cols = x.shape
x = x.reshape(x.size / chunk_size,chunk_size)
return x.sum(axis=1).reshape(rows,cols/chunk_size)但感觉不必要的复杂,有更好的方法吗？也许内置？
def sum_chunk(x,chunk_size,axis=-1):
shape = x.shape
if axis < 0:
axis += x.ndim
shape = shape[:axis] + (-1,chunk_size) + shape[axis+1:]
x = x.reshape(shape)
return x.sum(axis=axis+1)
>>> a = np.arange(24).reshape(4,6)
>>> a
array([[ 0,1,5],[ 6,[12,14,15,16,17],[18,20,21,22,23]])
>>> sum_chunk(a,2)
array([[ 1,9],[13,17,21],[25,29,33],[37,41,45]])
>>> sum_chunk(a,axis=0)
array([[ 6,12,16],[30,32,34,36,38,40]])总结
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