概述
本文实例讲述了python实现将英文单词表示的数字转换成阿拉伯数字的方法。分享给大家供大家参考。具体实现方法如下:
import re _kNown = { 'zero': 0,'one': 1,'two': 2,'three': 3,'four': 4,'five': 5,'six': 6,'seven': 7,'eight': 8,'nine': 9,'ten': 10,'eleven': 11,'twelve': 12,'thirteen': 13,'fourteen': 14,'fifteen': 15,'sixteen': 16,'seventeen': 17,'eighteen': 18,'nineteen': 19,'twenty': 20,'thirty': 30,'forty': 40,'fifty': 50,'sixty': 60,'seventy': 70,'eighty': 80,'ninety': 90 } def spoken_word_to_number(n): """Assume n is a positive integer". assert _positive_integer_number('nine hundred') == 900 assert spoken_word_to_number('one hundred') == 100 assert spoken_word_to_number('eleven') == 11 assert spoken_word_to_number('twenty two') == 22 assert spoken_word_to_number('thirty-two') == 32 assert spoken_word_to_number('forty two') == 42 assert spoken_word_to_number('two hundred thirty two') == 232 assert spoken_word_to_number('two thirty two') == 232 assert spoken_word_to_number('nineteen hundred eighty nine') == 1989 assert spoken_word_to_number('nineteen eighty nine') == 1989 assert spoken_word_to_number('one thousand nine hundred and eighty nine') == 1989 assert spoken_word_to_number('nine eighty') == 980 assert spoken_word_to_number('nine two') == 92 # wont be able to convert this one assert spoken_word_to_number('nine thousand nine hundred') == 9900 assert spoken_word_to_number('one thousand nine hundred one') == 1901 """ n = n.lower().strip() if n in _kNown: return _kNown[n] else: inputWordArr = re.split('[ -]',n) assert len(inputWordArr) > 1 #all single words are kNown #Check the pathological case where hundred is at the end or thousand is at end if inputWordArr[-1] == 'hundred': inputWordArr.append('zero') inputWordArr.append('zero') if inputWordArr[-1] == 'thousand': inputWordArr.append('zero') inputWordArr.append('zero') inputWordArr.append('zero') if inputWordArr[0] == 'hundred': inputWordArr.insert(0,'one') if inputWordArr[0] == 'thousand': inputWordArr.insert(0,'one') inputWordArr = [word for word in inputWordArr if word not in ['and','minus','negative']] currentPosition = 'unit' prevPosition = None output = 0 for word in reversed(inputWordArr): if currentPosition == 'unit': number = _kNown[word] output += number if number > 9: currentPosition = 'hundred' else: currentPosition = 'ten' elif currentPosition == 'ten': if word != 'hundred': number = _kNown[word] if number < 10: output += number*10 else: output += number #else: nothing special currentPosition = 'hundred' elif currentPosition == 'hundred': if word not in [ 'hundred','thousand']: number = _kNown[word] output += number*100 currentPosition = 'thousand' elif word == 'thousand': currentPosition = 'thousand' else: currentPosition = 'hundred' elif currentPosition == 'thousand': assert word != 'hundred' if word != 'thousand': number = _kNown[word] output += number*1000 else: assert "Can't be here" == None return(output)
希望本文所述对大家的Python程序设计有所帮助。
总结
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