SELECT
(SELECT COUNT(*) FROM Toys WHERE little_kid_id = 900)+
(SELECT COUNT(*) from Games WHERE little_kid1 = 900
OR little_kid2 = 900
OR little_kid3 = 900)
AS SumCount
瞧!@H_502_1@
如何在两个不同的表上一起添加两个count(*)结果?
SELECT
(SELECT COUNT(*) FROM Toys WHERE little_kid_id = 900)+
(SELECT COUNT(*) from Games WHERE little_kid1 = 900
OR little_kid2 = 900
OR little_kid3 = 900)
AS SumCount
瞧!@H_502_1@