好吧,如果您不太担心准确性,那很容易。平凡的方法有什么问题?
function timeDifference(current, prevIoUs) {
var msPerMinute = 60 * 1000;
var msPerHour = msPerMinute * 60;
var msPerDay = msPerHour * 24;
var msPerMonth = msPerDay * 30;
var msPerYear = msPerDay * 365;
var elapsed = current - prevIoUs;
if (elapsed < msPerMinute) {
return Math.round(elapsed/1000) + ' seconds ago';
}
else if (elapsed < msPerHour) {
return Math.round(elapsed/msPerMinute) + ' minutes ago';
}
else if (elapsed < msPerDay ) {
return Math.round(elapsed/msPerHour ) + ' hours ago';
}
else if (elapsed < msPerMonth) {
return 'approximately ' + Math.round(elapsed/msPerDay) + ' days ago';
}
else if (elapsed < msPerYear) {
return 'approximately ' + Math.round(elapsed/msPerMonth) + ' months ago';
}
else {
return 'approximately ' + Math.round(elapsed/msPerYear ) + ' years ago';
}
}
如果这会让您感到困扰1 day
,1 days
则可能需要对其进行调整以更好地处理奇异值(例如而不是)。