正如StaxMan已经建议的那样，你可以通过编写a BeanDeserializerModifier并通过进行注册来实现SimpleModule。下面的示例应该起作用：
public class UserEventDeserializer extends StdDeserializer<User> implements ResolvableDeserializer
{
private static final long serialVersionUID = 7923585097068641765L;
private final JsonDeserializer<?> defaultDeserializer;
public UserEventDeserializer(JsonDeserializer<?> defaultDeserializer)
{
super(User.class);
this.defaultDeserializer = defaultDeserializer;
}
@Override public User deserialize(JsonParser jp, DeserializationContext ctxt)
throws IOException, JsonProcessingException
{
User deserializedUser = (User) defaultDeserializer.deserialize(jp, ctxt);
// Special logic
return deserializedUser;
}
// for some reason you have to implement ResolvableDeserializer when modifying BeanDeserializer
// otherwise deserializing throws JsonMappingException??
@Override public void resolve(DeserializationContext ctxt) throws JsonMappingException
{
((ResolvableDeserializer) defaultDeserializer).resolve(ctxt);
}
public static void main(String[] args) throws JsonParseException, JsonMappingException, IOException
{
SimpleModule module = new SimpleModule();
module.setDeserializerModifier(new BeanDeserializerModifier()
{
@Override public JsonDeserializer<?> modifyDeserializer(DeserializationConfig config, BeanDescription beanDesc, JsonDeserializer<?> deserializer)
{
if (beanDesc.getBeanClass() == User.class)
return new UserEventDeserializer(deserializer);
return deserializer;
}
});
ObjectMapper mapper = new ObjectMapper();
mapper.registerModule(module);
User user = mapper.readValue(new File("test.json"), User.class);
}
}
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