Django admin只是一个普通的Django应用程序，因此没有什么可以阻止您实现第二级嵌套表单，但是恕我直言，这将是一种复杂的设计。也许这就是为什么没有规定的原因。
解决此问题的一种常见方法是，通过同时具有同一模型的ModelAdmin和Inline，在第一和第二（或第二和第三）级别之间链接到admin：
使用TrainingDate作为内联，向证书提供ModelAdmin。给CertificateInline一个附加字段“详细信息”，该字段是其ModelAdmin更改表单的链接。
models.py：
from django.core import urlresolvers
class Certificate(models.Model):
# ...
def changeform_link(self):
if self.id:
# Replace "myapp" with the name of the app containing
# your Certificate model:
changeform_url = urlresolvers.reverse(
'admin:myapp_certificate_change', args=(self.id,)
)
return u'<a href="%s" target="_blank">Details</a>' % changeform_url
return u''
changeform_link.allow_tags = True
changeform_link.short_description = '' # omit column header
admin.py：
# Certificate change form has training dates as inline
class TrainingDateInline(admin.StackedInline):
model = TrainingDate
class CertificateAdmin(admin.ModelAdmin):
inlines = [TrainingDateInline,]
admin.site.register(Certificate ,CertificateAdmin)
# Person has Certificates inline but rather
# than nesting inlines (not possible), shows a link to
# its own ModelAdmin's change form, for accessing TrainingDates:
class CertificateLinkInline(admin.TabularInline):
model = Certificate
# Whichever fields you want: (I usually use only a couple
# needed to identify the entry)
fields = ('cerfificate_no', 'certificate_date', 'changeform_link')
readonly_fields = ('changeform_link', )
class PersonAdmin(admin.ModelAdmin):
inlines = [CertificateLinkInline,]
admin.site.register(Person, PersonAdmin)
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