据我所知，没有办法以这种方式指定数据库端的排序，因为它过于特定于后端。你可能希望采用老式的Python排序：
class Foo(models.Model):
name = models.CharField(max_length=128)
Foo.objects.create(name='a10')
Foo.objects.create(name='a1')
Foo.objects.create(name='a2')
ordered = sorted(Foo.objects.all(), key=lambda n: (n[0], int(n[1:])))
print ordered # yields a1, a2, 10
如果你发现自己非常需要这种排序，那么建议models.Manager你为执行排序的模型制作一个自定义子类。就像是：
class FooManager(models.Manager):
def in_a_number_order(self, *args, **kwargs):
qs = self.get_query_set().filter(*args, **kwargs)
return sorted(qs, key=lambda n: (n[0], int(n[1:])))
class Foo(models.Model):
... as before ...
objects = FooManager()
print Foo.objects.in_a_number_order()
print Foo.objects.in_a_number_order(id__in=[5, 4, 3]) # or any filtering expression
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