您可以使用itertools.groupby对:Entry列表中出现的行进行分组：
import itertools as it
filename='test.dat'
with open(filename,'r') as f:
for key,group in it.groupby(f,lambda line: line.startswith(':Entry')):
if not key:
group = list(group)
print(group)
产量
['- Name\n', 'John Doe\n', '\n', '- Date\n', '20/12/1979\n']
['\n', '-Name\n', 'Jane Doe\n', '- Date\n', '21/12/1979\n']
或者，要处理组，您实际上不需要转换group为列表：
with open(filename,'r') as f:
for key,group in it.groupby(f,lambda line: line.startswith(':Entry')):
if not key:
for line in group:
...
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