这是扁平化嵌套序列的另一种方法。将序列展平后，可以很容易地进行检查以找到项目数。
def flatten(seq, container=None):
if container is None:
container = []
for s in seq:
try:
iter(s) # check if it's iterable
except TypeError:
container.append(s)
else:
flatten(s, container)
return container
c = flatten([(1,2),(3,4),(5,[6,7,['a','b']]),['c','d',('e',['f','g','h'])]])
print(c)
print(c.count('g'))
d = flatten([[[1,(1,),((1,(1,))), [1,[1,[1,[1]]]], 1, [1, [1, (1,)]]]]])
print(d)
print(d.count(1))
上面的代码打印：
[1, 2, 3, 4, 5, 6, 7, 'a', 'b', 'c', 'd', 'e', 'f', 'g', 'h']
1
[1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1]
12
602392714
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