我怀疑您只是对从转换char为int，这是隐式的：
for (int i = 0; i < text.length(); i++)
{
char c = text.charAt(i);
int value = c;
System.out.println(value);
}
for (int i = 0; i < text.length(); i++)
{
int codePoint = text.codePointAt(i);
// Skip over the second char in a surrogate pair
if (codePoint > 0xffff)
{
i++;
}
System.out.println(codePoint);
}
602392714
清零编程群