下面的实现是幼稚的,谷歌为“ currying python”提供了更准确的例子。
def curry(x, argc=None):
if argc is None:
argc = x.func_code.co_argcount
def p(*a):
if len(a) == argc:
return x(*a)
def q(*b):
return x(*(a + b))
return curry(q, argc - len(a))
return p
@curry
def myfun(a,b,c):
print '%d-%d-%d' % (a,b,c)
myfun(11,22,33)
myfun(44,55)(66)
myfun(77)(88)(99)