使用其他两个日期（提前三个小时和之后三个小时）进行比较。然后使用确认您要解析的日期在这两个边界之间compareTo()。
您确实不应该在班级名称中输入数字，但这是一个与答案无关的样式问题。
public class SO31132861 {
public static void main(String[] args) {
SimpleDateFormat df = new SimpleDateFormat("yyyyMMddHHmmss");
df.setLenient(false);
System.out.println(tryParse(df, "20160630231110"));
System.out.println(tryParse(df, "20150228231100"));
System.out.println(tryParse(df, "20160229231100"));
System.out.println(tryParse(df, "21000229231100")); // 29th Feb on non-leap year 2100
System.out.println(tryParse(df, "20160631231110")); // 31st Jun invalid day
System.out.println(tryParse(df, "20160229231160")); // Second > 59
System.out.println(tryParse(df, "20150229231100")); // 29th Feb on non-leap year 2015
System.out.println(tryParse(df, "20150228241100")); // Hour > 23
}
private static Boolean tryParse(DateFormat df, String s) {
Boolean valid=false;
try {
Date threeHoursBefore = new Date();
threeHoursBefore.setTime(System.currentTimeMillis() - (3*60*60*1000));
Date threeHoursAfter = new Date();
threeHoursAfter.setTime(System.currentTimeMillis() + (3*60*60*1000));
Date dateToParse= df.parse(s);
valid=dateToParse.compareTo(threeHoursBefore) > 0 && dateToParse.compareTo(threeHoursAfter) < 0;
} catch (ParseException e) {
valid=false;
}
return valid;
}
}
602392714
清零编程群