我用熊猫解决了这个问题。因为我们要保留文档ID和术语ID。
from pandas import DataFrame
# A sparse matrix in dictionary form (can be a sqlite database). Tuples contains doc_id and term_id.
doc_term_dict={('d1','t1'):12, ('d2','t3'):10, ('d3','t2'):5}
#extract all unique documents and terms ids and intialize a empty dataframe.
rows = set([d for (d,t) in doc_term_dict.keys()])
cols = set([t for (d,t) in doc_term_dict.keys()])
df = DataFrame(index = rows, columns = cols )
df = df.fillna(0)
#assign all nonzero values in dataframe
for key, value in doc_term_dict.items():
df[key[1]][key[0]] = value
print df
输出：
t2 t3 t1
d2 0 10 0
d3 5 0 0
d1 0 0 12
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