看起来您正在进行cesar密码加密，因此您可以尝试执行以下操作：
strs = 'abcdefghijklmnopqrstuvwxyz' #use a string like this, instead of ord()
def shifttext(shift):
inp = raw_input('Input text here: ')
data = []
for i in inp: #iterate over the text not some list
if i.strip() and i in strs: # if the char is not a space ""
data.append(strs[(strs.index(i) + shift) % 26])
else:
data.append(i) #if space the simply append it to data
output = ''.join(data)
return output
In [2]: shifttext(3)
Input text here: how are you?
Out[2]: 'krz duh brx?'
In [3]: shifttext(3)
Input text here: Fine.
Out[3]: 'Flqh.'
strs[(strs.index(i) + shift) % 26]：线以上手段找到字符的索引i中strs，然后添加移位值it.Now，对最终值（索引+偏移）申请％26向得到移位索引。传递给时，此移位索引会strs[new_index] 产生所需的移位字符。
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