您将要找到将第一个轨道的第i个点连接到第二个轨道的第i个点的直线的方程式。然后，您可以使用i和z作为参数，在所有可能的值上变化以找到X和Y。
例：
import numpy as np
import matplotlib
import matplotlib.pyplot as plt
from mpl_toolkits.mplot3d import Axes3D
Z1 = 8.0
Z2 = 9.0
font = {'size' : 18}
matplotlib.rc('font', **font)
fig = plt.figure()
ax = fig.add_subplot(111, projection='3d')
t = np.linspace(0, 2 * np.pi, 100)
x = np.cos(t)
y = np.sin(2 * t)
N = len(x)
z = np.zeros(N)
z[:,] = Z1
t = np.linspace(0, 2 * np.pi, 100)
x2 = 2 * np.cos(t)
y2 = 2 * np.sin(2*t)
N = len(x2)
z2 = np.zeros(N)
z2[:,] = Z2
#Plot the first orbit
ax.plot(x, y, z, 'k-', linewidth=3.0)
#Plot second orbit
ax.plot(x2, y2, z2, 'k-', linewidth=3.0)
i, h = np.meshgrid(np.arange(len(x)), np.linspace(Z1, Z2, 10))
X = (x2[i] - x[i]) / (Z2 - Z1) * (h - Z1) + x[i]
Y = (y2[i] - y[i]) / (Z2 - Z1) * (h - Z1) + y[i]
surf = ax.plot_surface(X, Y, h, color='m', alpha=0.3,
linewidth=0)
#Set axis and things
ax.set_xticks([1.0,1.5,2])
ax.set_yticks([32,35,38])
ax.set_ylabel('$||u||_{2}$', fontsize=26, rotation=0, labelpad = 26)
ax.set_xlabel('$h$', fontsize=26)
ax.set_zlabel('$\mu$', fontsize=26, rotation=90)
plt.tight_layout()
plt.show()
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