这是一种使正则表达式与所需格式的任何日期匹配的方法（尽管您显然可以调整逗号是否可选，添加月份缩写等等）：
years = r'((?:19|20)\d\d)'
pattern = r'(%%s) +(%%s), *%s' % years
thirties = pattern % (
"September|April|June|November",
r'0?[1-9]|[12]\d|30')
thirtyones = pattern % (
"January|March|May|July|August|October|December",
r'0?[1-9]|[12]\d|3[01]')
fours = '(?:%s)' % '|'.join('%02d' % x for x in range(4, 100, 4))
feb = r'(February) +(?:%s|%s)' % (
r'(?:(0?[1-9]|1\d|2[0-8])), *%s' % years, # 1-28 any year
r'(?:(29), *((?:(?:19|20)%s)|2000))' % fours) # 29 leap years only
result = '|'.join('(?:%s)' % x for x in (thirties, thirtyones, feb))
r = re.compile(result)
print result
然后我们有：
>>> r.match('January 30, 2001') is not None
True
>>> r.match('January 31, 2001') is not None
True
>>> r.match('January 32, 2001') is not None
False
>>> r.match('February 32, 2001') is not None
False
>>> r.match('February 29, 2001') is not None
False
>>> r.match('February 28, 2001') is not None
True
>>> r.match('February 29, 2000') is not None
True
>>> r.match('April 30, 1908') is not None
True
>>> r.match('April 31, 1908') is not None
False
您可能会问，这个光荣的正则表达式是什么？
>>> print result
(?:(September|April|June|November) +(0?[1-9]|[12]\d|30), *((?:19|20)\d\d))|(?:(January|March|May|July|August|October|December) +(0?[1-9]|[12]\d|3[01]), *((?:19|20)\d\d))|(?:February +(?:(?:(0?[1-9]|1\d|2[0-8]), *((?:19|20)\d\d))|(?:(29), *((?:(?:19|20)(?:04|08|12|16|20|24|28|32|36|40|44|48|52|56|60|64|68|72|76|80|84|88|92|96))|2000))))
（我最初打算对可能的日期进行逐个枚举，但基本上我还是用手写的方式写了整个粗略的东西，但无论如何都是四个的倍数。）
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