您好, 欢迎来到 !    登录 | 注册 | | 设为首页 | 收藏本站

如何计算一个点与另一个点相距一定距离的纬度?

如何计算一个点与另一个点相距一定距离的纬度?

我们将需要一种方法,该方法会在给定方位角和距源点的距离时返回目标点。幸运的是,克里斯·韦尼斯(ChrisVeness)在“计算距离,纬度点之间的距离,方位及更多”方面有一个很好的JavaScript实现。

以下内容已适应与google.maps.LatLng该类一起使用:

Number.prototype.toRad = function() {
   return this * Math.PI / 180;
}

Number.prototype.toDeg = function() {
   return this * 180 / Math.PI;
}

google.maps.LatLng.prototype.destinationPoint = function(brng, dist) {
   dist = dist / 6371;  
   brng = brng.toRad();

   var lat1 = this.lat().toRad(), lon1 = this.lng().toRad();

   var lat2 = Math.asin(Math.sin(lat1) * Math.cos(dist) + 
                        Math.cos(lat1) * Math.sin(dist) * Math.cos(brng));

   var lon2 = lon1 + Math.atan2(Math.sin(brng) * Math.sin(dist) *
                                Math.cos(lat1), 
                                Math.cos(dist) - Math.sin(lat1) *
                                Math.sin(lat2));

   if (isNaN(lat2) || isNaN(lon2)) return null;

   return new google.maps.LatLng(lat2.toDeg(), lon2.toDeg());
}

您只需按以下方式使用它:

var pointA = new google.maps.LatLng(25.48, -71.26); 
var radiusInKm = 10;

var pointB = pointA.destinationPoint(90, radiusInKm);

这是使用Google Maps APIv3的完整示例:

<!DOCTYPE html>
<html> 
<head> 
   <Meta http-equiv="content-type" content="text/html; charset=UTF-8"/> 
   <title>Google Maps Geometry</title> 
   <script src="http://maps.google.com/maps/api/js?sensor=false" 
           type="text/javascript"></script> 
</head> 
<body> 
   <div id="map" style="width: 400px; height: 300px"></div>

   <script type="text/javascript"> 
      Number.prototype.toRad = function() {
         return this * Math.PI / 180;
      }

      Number.prototype.toDeg = function() {
         return this * 180 / Math.PI;
      }

      google.maps.LatLng.prototype.destinationPoint = function(brng, dist) {
         dist = dist / 6371;  
         brng = brng.toRad();

         var lat1 = this.lat().toRad(), lon1 = this.lng().toRad();

         var lat2 = Math.asin(Math.sin(lat1) * Math.cos(dist) + 
                              Math.cos(lat1) * Math.sin(dist) * Math.cos(brng));

         var lon2 = lon1 + Math.atan2(Math.sin(brng) * Math.sin(dist) *
                                      Math.cos(lat1), 
                                      Math.cos(dist) - Math.sin(lat1) *
                                      Math.sin(lat2));

         if (isNaN(lat2) || isNaN(lon2)) return null;

         return new google.maps.LatLng(lat2.toDeg(), lon2.toDeg());
      }

      var pointA = new google.maps.LatLng(40.70, -74.00);   // Circle center
      var radius = 10;                                      // 10km

      var mapOpt = { 
         mapTypeId: google.maps.MapTypeId.TERRAIN,
         center: pointA,
         zoom: 10
      };

      var map = new google.maps.Map(document.getElementById("map"), mapOpt);

      // Draw the circle
      new google.maps.Circle({
         center: pointA,
         radius: radius * 1000,       // Convert to meters
         fillColor: '#FF0000',
         fillOpacity: 0.2,
         map: map
      });

      // Show marker at circle center
      new google.maps.Marker({
         position: pointA,
         map: map
      });

      // Show marker at destination point
      new google.maps.Marker({
         position: pointA.destinationPoint(90, radius),
         map: map
      });
   </script> 
</body> 
</html>

pointA在北极附近绘制,半径为1,000km:

  var pointA = new google.maps.LatLng(85, 0);   // Close to north pole
  var radius = 1000;                            // 1000km
其他 2022/1/1 18:14:43 有543人围观

撰写回答


你尚未登录,登录后可以

和开发者交流问题的细节

关注并接收问题和回答的更新提醒

参与内容的编辑和改进,让解决方法与时俱进

请先登录

推荐问题


联系我
置顶