使用@WarrenWeckesser在此处np.diff给出的和方法来查找数组中的零游程：
import numpy as np
def zero_runs(a): # from link
iszero = np.concatenate(([0], np.equal(a, 0).view(np.int8), [0]))
absdiff = np.abs(np.diff(iszero))
ranges = np.where(absdiff == 1)[0].reshape(-1, 2)
return ranges
a = [34,2,3,22,22,22,22,22,22,18,90,5,-55,-19,22,6,6,6,6,6,6,6,6,23,53,1,5,-42,82]
zero_runs(np.diff(a))
Out[87]:
array([[ 3, 8],
[15, 22]], dtype=int32)
然后可以根据运行开始和结束之间的差异来过滤：
runs = zero_runs(np.diff(a))
runs[runs[:, 1]-runs[:, 0]>5] # runs of 7 or more, to illustrate filter
Out[96]: array([[15, 22]], dtype=int32)
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