要解密这种加密形式，您将需要获得Rijndael版本。在这里可以找到一个。然后，您将需要模拟PHP Mcrypt模块中使用的键和文本填充。它们增加'\0'了填充文本和键的正确大小。他们使用的是256位块大小，并且您提供的密钥使用的密钥大小为128（如果您提供更大的密钥，则密钥大小可能会增加）。不幸的是，我链接到的Python实现一次只能编码一个块。我创建了python函数，用于模拟Python中的加密（用于测试）和解密
import rijndael
import base64
KEY_SIZE = 16
BLOCK_SIZE = 32
def encrypt(key, plaintext):
padded_key = key.ljust(KEY_SIZE, '\0')
padded_text = plaintext + (BLOCK_SIZE - len(plaintext) % BLOCK_SIZE) * '\0'
# Could also be one of
#if len(plaintext) % BLOCK_SIZE != 0:
# padded_text = plaintext.ljust((len(plaintext) / BLOCK_SIZE) + 1 * BLOCKSIZE), '\0')
# -OR-
#padded_text = plaintext.ljust((len(plaintext) + (BLOCK_SIZE - len(plaintext) % BLOCK_SIZE)), '\0')
r = rijndael.rijndael(padded_key, BLOCK_SIZE)
ciphertext = ''
for start in range(0, len(padded_text), BLOCK_SIZE):
ciphertext += r.encrypt(padded_text[start:start+BLOCK_SIZE])
encoded = base64.b64encode(ciphertext)
return encoded
def decrypt(key, encoded):
padded_key = key.ljust(KEY_SIZE, '\0')
ciphertext = base64.b64decode(encoded)
r = rijndael.rijndael(padded_key, BLOCK_SIZE)
padded_text = ''
for start in range(0, len(ciphertext), BLOCK_SIZE):
padded_text += r.decrypt(ciphertext[start:start+BLOCK_SIZE])
plaintext = padded_text.split('\x00', 1)[0]
return plaintext
可以如下使用：
key = 'MyKey'
text = 'test'
encoded = encrypt(key, text)
print repr(encoded)
# prints 'I+KlvwIK2e690lPLDQMMUf5kfZmdZRIexYJp1SLWRJY='
decoded = decrypt(key, encoded)
print repr(decoded)
# prints 'test'
$ PHP -a
Interactive shell
PHP > $key = 'MyKey';
PHP > $text = 'test';
PHP > $output = mcrypt_encrypt(MCRYPT_RIJNDAEL_256, $key, $text, MCRYPT_MODE_ECB);
PHP > $encoded = base64_encode($output);
PHP > echo $encoded;
I+KlvwIK2e690lPLDQMMUf5kfZmdZRIexYJp1SLWRJY=
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