>>> A = [3, 4, 6, 7]
>>> B = [1, 3, 6, 3]
>>> map(operator.sub, A, B)
[2, 1, 0, 4]
就像下面提到的@SethMMorton一样,在python3中,您需要使用它
>>> A = [3, 4, 6, 7]
>>> B = [1, 3, 6, 3]
>>> list(map(operator.sub, A, B))
[2, 1, 0, 4]
因为,Python中的map会返回迭代器。
如何从数学上减去python中的两个列表?
>>> A = [3, 4, 6, 7]
>>> B = [1, 3, 6, 3]
>>> map(operator.sub, A, B)
[2, 1, 0, 4]
就像下面提到的@SethMMorton一样,在python3中,您需要使用它
>>> A = [3, 4, 6, 7]
>>> B = [1, 3, 6, 3]
>>> list(map(operator.sub, A, B))
[2, 1, 0, 4]
因为,Python中的map会返回迭代器。