众所周知，重复的字符串连接效率很低，因为Python字符串是不可变的。我会去
strprime = str(prime)
以我的基准而言，这始终是最快的解决方案。这是我的小基准程序：
import decimal
def f1(x):
''' DeFinition by OP '''
strprime = ""
while x > 0:
strprime += str(x%10)
x //= 10
return strprime
def digits(x):
while x > 0:
yield x % 10
x //= 10
def f2(x):
''' Using string.join() to avoid repeated string concatenation '''
return "".join((chr(48 + d) for d in digits(x)))
def f3(x):
''' Plain str() '''
return str(x)
def f4(x):
''' Using Decimal class'''
return decimal.Decimal(x).to_eng_string()
x = 2**100
if __name__ == '__main__':
import timeit
for i in range(1,5):
funcName = "f" + str(i)
print(funcName+ ": " + str(timeit.timeit(funcName + "(x)", setup="from __main__ import " + funcName + ", x")))
对我来说，这是打印的（使用Python 2.7.10）：
f1: 15.3430171013
f2: 20.8928260803
f3: 0.310356140137
f4: 2.80087995529
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