如果您在指向用户的属性上具有关联(例如Credit\Entity\UserCreditHistory#user
,从示例中选取),那么语法非常简单:
public function getHistory($users) {
$qb = $this->entityManager->createQueryBuilder();
$qb
->select('a', 'u')
->from('Credit\Entity\UserCreditHistory', 'a')
->leftJoin('a.user', 'u')
->where('u = :user')
->setParameter('user', $users)
->orderBy('a.created_at', 'DESC');
return $qb->getQuery()->getResult();
}
由于您要在此处对合并结果应用条件,因此使用LEFT JOIN
或JOIN
完全相同。
如果没有可用的关联,则查询如下所示
public function getHistory($users) {
$qb = $this->entityManager->createQueryBuilder();
$qb
->select('a', 'u')
->from('Credit\Entity\UserCreditHistory', 'a')
->leftJoin(
'User\Entity\User',
'u',
\Doctrine\ORM\Query\Expr\Join::WITH,
'a.user = u.id'
)
->where('u = :user')
->setParameter('user', $users)
->orderBy('a.created_at', 'DESC');
return $qb->getQuery()->getResult();
}
这将产生一个结果集,如下所示:
array(
array(
0 => UserCreditHistory instance,
1 => Userinstance,
),
array(
0 => UserCreditHistory instance,
1 => Userinstance,
),
// ...
)