根据您要处理项目的顺序：
import itertools
for items in itertools.izip(deque1, deque2, deque3):
for item in items:
some_action(item)
for item in itertools.chain(deque1, deque2, deque3):
some_action(item)
我建议这样做，以避免对实际的双端队列或双端队列进行硬编码：
deques = [deque1, deque2, deque3]
for item in itertools.chain(*deques):
some_action(item)
为了证明上述方法的顺序不同：
>>> a = range(5)
>>> b = range(5)
>>> c = range(5)
>>> d = [a, b, c]
>>>
>>> for items in itertools.izip(*d):
... for item in items:
... print item,
...
0 0 0 1 1 1 2 2 2 3 3 3 4 4 4
>>>
>>> for item in itertools.chain(*d):
... print item,
...
0 1 2 3 4 0 1 2 3 4 0 1 2 3 4
>>>
602392714
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