def chunks(lst, n):
"""Yield successive n-sized chunks from lst."""
for i in range(0, len(lst), n):
yield lst[i:i + n]
import pprint
pprint.pprint(list(chunks(range(10, 75), 10)))
[[10, 11, 12, 13, 14, 15, 16, 17, 18, 19],
[20, 21, 22, 23, 24, 25, 26, 27, 28, 29],
[30, 31, 32, 33, 34, 35, 36, 37, 38, 39],
[40, 41, 42, 43, 44, 45, 46, 47, 48, 49],
[50, 51, 52, 53, 54, 55, 56, 57, 58, 59],
[60, 61, 62, 63, 64, 65, 66, 67, 68, 69],
[70, 71, 72, 73, 74]]
如果您使用的是Python 2，则应使用xrange()而不是range()：
def chunks(lst, n):
"""Yield successive n-sized chunks from lst."""
for i in xrange(0, len(lst), n):
yield lst[i:i + n]
您也可以简单地使用列表推导而不是编写函数，尽管将这样的操作封装在命名函数中是个好主意，这样您的代码就更容易理解了。Python 3：
[lst[i:i + n] for i in range(0, len(lst), n)]
Python 2版本：
[lst[i:i + n] for i in xrange(0, len(lst), n)]
602392714
清零编程群