>>> df['string'].str.split(',', expand=True)
0 1 2
0 astring isa string
1 another string la
2 123 232 another
>>>
带有列名：
>>> df['string'].str.split(',', expand=True).rename(columns = lambda x: "string"+str(x+1))
string1 string2 string3
0 astring isa string
1 another string la
2 123 232 another
Python> = 3.6 f字符串的情况更加整洁：
>>> (df['string'].str.split(',', expand=True)
... .rename(columns=lambda x: f"string_{x+1}"))
string_1 string_2 string_3
0 astring isa string
1 another string la
2 123 232 another
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