你是假设c直接跟随b这是情况并非如此。编译器将在该结构中填充x86上的几个字节，以align c。
正确的方法是在中声明结构的一对一映射ctypes：
from ctypes import *
class object_t(Structure):
_fields_ = [
('a', c_uint8),
('b', c_uint8),
('c', c_uint32),
('d', POINTER(c_uint8)),
]
不，您可以获得任何以这种类型的成员的值。
C示例库：
#include <stdint.h>
#include <stdlib.h>
struct object_t {
uint8_t a;
uint8_t b;
uint32_t c;
uint8_t* d;
};
static struct object_t object = {'a', 'b', 12345, NULL};
struct object_t * func1(void)
{
return &object;
}
void func2(void(*callback)(struct object_t *))
{
callback(&object);
}
从Python使用它：
from ctypes import *
class object_t(Structure):
_fields_ = [
('a', c_uint8),
('b', c_uint8),
('c', c_uint32),
('d', POINTER(c_uint8)),
]
callback_t = CFUNCTYPE(None, POINTER(object_t))
lib = CDLL('./file.dll')
func1 = lib.func1
func1.argtypes = None
func1.restype = POINTER(object_t)
func2 = lib.func2
func2.argtypes = [callback_t]
func2.restype = None
ret = func1()
a = ret.contents.a
b = ret.contents.b
c = ret.contents.c
d = ret.contents.d
def mycallback(obj):
a = obj.contents.a
b = obj.contents.b
c = obj.contents.c
d = obj.contents.d
func2(callback_t(mycallback))
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