这可以实现,但是您必须通过将[XmlSerializerFormat]
属性应用于DataContract 来覆盖默认的序列化程序。尽管可以做到,但它的性能不如默认的序列化程序,因此请谨慎使用。
以下类结构将为您提供您所追求的结果:
using ...
using System.Runtime.Serialization;
using System.ServiceModel;
using System.Xml.Serialization;
[DataContract]
[XmlSerializerFormat]
public class root
{
public distance distance=new distance();
}
[DataContract]
public class distance
{
[DataMember, XmlAttribute]
public string units="m";
[DataMember, XmlText]
public int value=1000;
}
您可以使用以下代码对此进行测试:
root mc = new root();
XmlSerializer ser = new XmlSerializer(typeof(root));
StringWriter sw = new StringWriter();
ser.Serialize(sw, mc);
Console.WriteLine(sw.ToString());
Console.ReadKey();
输出将是:
<?xml version="1.0" encoding="utf-16"?>
<root xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<distance units="m">1000</distance>
</root>