with open('file path', 'a') as f:
data = f.read()
#do something with data
要么
f = open(os.path.join(dir,str1),'r')
f.close()
打开文件的最pythonic方法是什么?
with open('file path', 'a') as f:
data = f.read()
#do something with data
要么
f = open(os.path.join(dir,str1),'r')
f.close()