您好, 欢迎来到 !    登录 | 注册 | | 设为首页 | 收藏本站

有序打印的Python多处理子流程?

有序打印的Python多处理子流程?

如您所知,在这种情况下使用锁会杀死多进程,因为您实际上会让所有进程都等待当前持有STDOUT的“权限”的进程释放互斥量。但是,从逻辑上讲,并行运行并与功能/子流程同步打印是排他的。

相反,您可以做的是让主流程充当子流程的“打印机”,这样子流程一旦完成/出现错误,然后然后才将要打印的内容发送回主流程。对于似乎不是“实时”的打印,您似乎是非常满意的(无论如何也不能如前所述),因此该方法应该恰好为您服务。所以:

import multiprocessing as mp
import random  # just to add some randomness
from time import sleep

def foo(x):
    output = ["[Process {}]: foo:".format(x)]
    for i in range(5):
        output.append('[Process {}] in foo {}'.format(x, i))
        sleep(0.2 + 1 * random.random())
    return "\n".join(output)

if __name__ == '__main__':
    pool = mp.Pool(4)
    for res in pool.imap_unordered(foo, range(4)):
        print("[MAIN]: Process finished, response:")
        print(res)  # this will print as soon as one of the processes finishes/errors
    pool.close()

这会给你(当然是YMMV):

[MAIN]: Process finished, response:
[Process 2]: foo:
[Process 2] in foo 0
[Process 2] in foo 1
[Process 2] in foo 2
[Process 2] in foo 3
[Process 2] in foo 4
[MAIN]: Process finished, response:
[Process 0]: foo:
[Process 0] in foo 0
[Process 0] in foo 1
[Process 0] in foo 2
[Process 0] in foo 3
[Process 0] in foo 4
[MAIN]: Process finished, response:
[Process 1]: foo:
[Process 1] in foo 0
[Process 1] in foo 1
[Process 1] in foo 2
[Process 1] in foo 3
[Process 1] in foo 4
[MAIN]: Process finished, response:
[Process 3]: foo:
[Process 3] in foo 0
[Process 3] in foo 1
[Process 3] in foo 2
[Process 3] in foo 3
[Process 3] in foo 4

您可以观察到其他任何东西,包括以同样的方式出现错误

-如果您绝对必须使用其输出无法控制的功能,则可以包装子流程并捕获其STDOUT / STDERR,然后一旦完成(或引发异常),就可以将所有内容返回给流程’manager ‘打印到实际的STDOUT。通过这样的设置,我们可以foo()像:

def foo(x):
    print("[Process {}]: foo:".format(x))
    for i in range(5):
        print('[Process {}] in foo {}'.format(x, i))
        sleep(0.2 + 1 * random.random())
        if random.random() < 0.0625:  # let's add a 1/4 chance to err:
            raise Exception("[Process {}] A random exception is random!".format(x))
    return random.random() * 100  # just a random response, you can omit it

请注意,它非常高兴地不知道有什么东西试图破坏其操作模式。然后,我们将创建一个外部通用包装器(这样您就不必依赖于功能对其进行更改)实际上就 弄乱 了它的认行为(不仅是这个函数,还有它在运行时可能调用的所有其他东西):

def std_wrapper(args):
    try:
        from StringIO import StringIO  # ... for Python 2.x compatibility
    except ImportError:
        from io import StringIO
    import sys
    sys.stdout, sys.stderr = StringIO(), StringIO()  # replace stdout/err with our buffers
    # args is a list packed as: [0] process function name; [1] args; [2] kwargs; lets unpack:
    process_name = args[0]
    process_args = args[1] if len(args) > 1 else []
    process_kwargs = args[2] if len(args) > 2 else {}
    # get our method from its name, assuming global namespace of the current module/script
    process = globals()[process_name]
    response = None  # in case a call fails
    try:
        response = process(*process_args, **process_kwargs)  # call our process function
    except Exception as e:  # too broad but good enough as an example
        print(e)
    # rewind our buffers:
    sys.stdout.seek(0)
    sys.stderr.seek(0)
    # return everything packed as STDOUT, STDERR, PROCESS_RESPONSE | NONE
    return sys.stdout.read(), sys.stderr.read(), response

现在,我们需要的是调用此包装器而不是所需的包装器foo(),并为其提供有关代表我们调用的信息:

if __name__ == '__main__':
    pool = mp.Pool(4)
    # since we're wrapping the process we're calling, we need to send to the wrapper packed
    # data with instructions on what to call on our behalf.
    # info on args packing available in the std_wrapper function above.
    for out, err, res in pool.imap_unordered(std_wrapper, [("foo", [i]) for i in range(4)]):
        print("[MAIN]: Process finished, response: {}, STDOUT:".format(res))
        print(out.rstrip())  # remove the trailing space for niceness, print err if you want
    pool.close()

因此,如果您现在运行它,将会得到以下内容

[MAIN]: Process finished, response: None, STDOUT:
[Process 2]: foo:
[Process 2] in foo 0
[Process 2] in foo 1
[Process 2] A random exception is random!
[MAIN]: Process finished, response: 87.9658471743586, STDOUT:
[Process 1]: foo:
[Process 1] in foo 0
[Process 1] in foo 1
[Process 1] in foo 2
[Process 1] in foo 3
[Process 1] in foo 4
[MAIN]: Process finished, response: 38.929554421661194, STDOUT:
[Process 3]: foo:
[Process 3] in foo 0
[Process 3] in foo 1
[Process 3] in foo 2
[Process 3] in foo 3
[Process 3] in foo 4
[MAIN]: Process finished, response: None, STDOUT:
[Process 0]: foo:
[Process 0] in foo 0
[Process 0] in foo 1
[Process 0] in foo 2
[Process 0] in foo 3
[Process 0] in foo 4
[Process 0] A random exception is random!

尽管foo()只是打印掉或出错。当然,您可以使用此类包装器来调用任何函数,并将任何数量的args / kwargs传递给该函数

但是,等一下!如果我们可以像这样包装我们的函数过程,并捕获它们的STDOUT / STDERR,我们肯定可以将其变成装饰器,并通过简单的装饰将其用于代码中。因此,对于我的最终建议:

import functools
import multiprocessing
import random  # just to add some randomness
import time

def std_wrapper(func):
    @functools.wraps(func)  # we need this to unravel the target function name
    def caller(*args, **kwargs):  # and Now for the wrapper, nothing new here
        try:
            from StringIO import StringIO  # ... for Python 2.x compatibility
        except ImportError:
            from io import StringIO
        import sys
        sys.stdout, sys.stderr = StringIO(), StringIO()  # use our buffers instead
        response = None  # in case a call fails
        try:
            response = func(*args, **kwargs)  # call our wrapped process function
        except Exception as e:  # too broad but good enough as an example
            print(e)  # NOTE: the exception is also printed to the captured STDOUT
        # rewind our buffers:
        sys.stdout.seek(0)
        sys.stderr.seek(0)
        # return everything packed as STDOUT, STDERR, PROCESS_RESPONSE | NONE
        return sys.stdout.read(), sys.stderr.read(), response
    return caller

@std_wrapper  # decorate any function, it won't kNow you're siphoning its STDOUT/STDERR
def foo(x):
    print("[Process {}]: foo:".format(x))
    for i in range(5):
        print('[Process {}] in foo {}'.format(x, i))
        time.sleep(0.2 + 1 * random.random())
        if random.random() < 0.0625:  # let's add a 1/4 chance to err:
            raise Exception("[Process {}] A random exception is random!".format(x))
    return random.random() * 100  # just a random response, you can omit it

现在我们可以像以前一样调用包装函数了,而无需处理参数打包或任何类似的事情,因此我们回到了:

if __name__ == '__main__':
    pool = multiprocessing.Pool(4)
    for out, err, res in pool.imap_unordered(foo, range(4)):
        print("[MAIN]: Process finished, response: {}, STDOUT:".format(res))
        print(out.rstrip())  # remove the trailing space for niceness, print err if you want
    pool.close()

输出与前面的示例相同,但包装更好,更易于管理。

python 2022/1/1 18:43:49 有309人围观

撰写回答


你尚未登录,登录后可以

和开发者交流问题的细节

关注并接收问题和回答的更新提醒

参与内容的编辑和改进,让解决方法与时俱进

请先登录

推荐问题


联系我
置顶