这是一个半屁股解决方案，它不考虑时钟抖动或时钟调整。请参阅注释以了解解决方法。
import time
import datetime
# if for some reason this script is still running
# after a year, we'll stop after 365 days
for i in xrange(0,365):
# sleep until 2AM
t = datetime.datetime.today()
future = datetime.datetime(t.year,t.month,t.day,2,0)
if t.hour >= 2:
future += datetime.timedelta(days=1)
time.sleep((future-t).total_seconds())
# do 2AM stuff
602392714
清零编程群