要允许多个连续匹配，请使用超前/后退：
r'(?<=\.)\d+,\d+(?=\.)'
例：
>>> re.findall(r'(?<=\.)\d+,\d+(?=\.)', 'Test7.5,6.7,8.test')
['5,6', '7,8']
我们还可以根据需要使用超前执行拆分：
import re
def split_it(s):
pieces = re.split(r'\.(?=\d+,\d+\.)', s)
pieces[-1:] = pieces[-1].rsplit('.', 1) # split off extension
return pieces
测试：
>>> print split_it('Test1.0,0.csv')
['Test1', '0,0', 'csv']
>>> print split_it('Test2.wma')
['Test2', 'wma']
>>> print split_it('Test3.1100,456.jpg')
['Test3', '1100,456', 'jpg']
>>> print split_it('T.E.S.T.4.5,6.png')
['T.E.S.T.4', '5,6', 'png']
>>> print split_it('Test5,7,8.sss')
['Test5,7,8', 'sss']
>>> print split_it('Test6.2,3,4.png')
['Test6.2,3,4', 'png']
>>> print split_it('Test7.5,6.7,8.test')
['Test7', '5,6', '7,8', 'test']
602392714
清零编程群