您应该使用itertools.groupby：
t = [
['Name1', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '+'],
['Name1', '', '', '', '', '', 'b', '', '', '', '', '', '', '', '', '', '', '', '', '', ''],
['Name2', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', 'a', ''],
['Name3', '', '', '', '', '+', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '']
]
from itertools import groupby
# TODO: if you need to speed things up you can use operator.itemgetter
# for both sorting and grouping
for name, rows in groupby(sorted(t), lambda x:x[0]):
print join_rows(rows)
显然，您将在单独的函数中实现合并。例如这样：
def join_rows(rows):
def join_tuple(tup):
for x in tup:
if x:
return x
else:
return ''
return [join_tuple(x) for x in zip(*rows)]
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