不，结果应为1。
将赋值运算符（=）视为参考的赋值。
a = 1 #a references the integer object 1
b = a #b and a reference the same object
a = 2 #a Now references a new object (2)
print b # prints 1 because you changed what a references, not b
同时，这整个的区别真的是最重要的 可变 对象，如lists，而不是 一成不变的 状物体int，float和tuple。
现在考虑以下代码：
a=[] #a references a mutable object
b=a #b references the same mutable object
b.append(1) #change b a little bit
print a # [1] -- because a and b still reference the same object
# which was changed via b.
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