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如何在JPA中映射复合主键,其中主键的一部分是外键

如何在JPA中映射复合主键,其中主键的一部分是外键

嗯,您遇到的基本问题是根据列而不是实体进行思考,尽管由于问题有点棘手,所以这可能是不公平的陈述。基本问题是如何将实体作为复合键的一部分包含在内,我在这里找到了答案:如何在JPA中创建包含@ManyToOne属性作为@EmbeddedId的复合主键?。设备:

@Entity
@Table(name = "devices")
public class Device
{
    @Id
    @Column(name = "device_nbr")
    private Long number;

    @Column(name = "device_id", length = 20)
    private String deviceid;

    @ManyToOne(fetch=FetchType.EAGER, cascade=CascadeType.ALL)
    @JoinColumns({@JoinColumn(name="dev_type", referencedColumnName="dev_type"), @JoinColumn(name="model_nbr", referencedColumnName="model_nbr")})
    private DeviceModel deviceModel;

    // This creates a foreign key constraint, but otherwise doesn't function
    // deviceType must be accessed through deviceModel
    // note, it can be used for explicit selects, e.g., "select d.deviceType from Device d"
    @OneToOne(fetch=FetchType.EAGER, cascade=CascadeType.ALL)
    @JoinColumn(name="dev_type", referencedColumnName="dev_type", insertable=false, updatable=false)
    private DeviceType deviceType;

    @Column(name = "unit_addr", length = 32)
    private String unitAddress;

设备型号:

@Entity
@Table(name = "devmodels")
public class DeviceModel
{
    @EmbeddedId
    private DeviceModelId id;

    @ManyToOne(fetch=FetchType.EAGER, cascade=CascadeType.ALL)
    @JoinColumn(name="dev_type")
    @MapsId("deviceType")
    private DeviceType deviceType;

    @Column(name = "model_desc", length=20)
    private String  description;

DeviceModelId:

@Embeddable
public class DeviceModelId implements Serializable
{
    private static final long   serialVersionUID    = -8173857210615808268L;
    private Integer deviceType;
    @Column(name="model_nbr")
    private Integer modelNumber;

请注意,我使用@Embeddable@EmbeddedId。它只是更新的,我已经阅读了JPA提供程序的评论,它比首选@IdClass。我认为这也使列命名更容易一些,但我不记得了。

设备类型:

@Entity
@Table(name = "devtypes")
public class DeviceType
{
    @Id
    @GeneratedValue
    @Column(name = "dev_type")
    private Integer deviceType;

    @Column(name = "dev_desc", length = 16)
    private String  description;

诀窍是@MapsIdDeviceModel。这样就可以在CompositeKey中使用实体。该字段上的@JoinColumn启用了该字段的命名。使用它的唯一技巧是手动创建DeviceTypeId:

DeviceModel model = new DeviceModel();
DeviceModelId modelId = new DeviceModelId();
modelId.setModelNumber(654321);
// have to have a DeviceType to create a DeviceModel
model.setDeviceType(type);
model.setId(modelId);

这将创建以下模式,该模式似乎与您的模式匹配。

create table devices (device_nbr bigint not null, device_id varchar(20), unit_addr varchar(32), dev_type integer, model_nbr integer, primary key (device_nbr))
create table devmodels (dev_type integer not null, model_nbr integer not null, model_desc varchar(20), primary key (dev_type, model_nbr))
create table devtypes (dev_type integer not null, dev_desc varchar(16), primary key (dev_type))
alter table devices add constraint FK8q0a886v04gg0qv261x1b2qrf foreign key (dev_type, model_nbr) references devmodels
alter table devices add constraint FKb72a7hq5phwjtbhaglobdkgji foreign key (dev_type) references devtypes
alter table devmodels add constraint FK4xlwyd2gwpbs4g4hdckyb11oj foreign key (dev_type) references devtypes
其他 2022/1/1 18:16:29 有576人围观

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