在跟踪了许多帖子和教程超过24小时后，我知道我没有正确发送URL参数。而且我还了解到使用 REST API调用相对容易一些。我解决了我的HTTP错误代码400，并从服务器获取了响应。这是我的问题的工作代码。
try {
httpClient = HttpClients.createDefault();
httpPost = new HttpPost("https://appem.totango.com/api/v1/search/accounts/health_dist");
List<NameValuePair> headers = new ArrayList<NameValuePair>(); //ArrayList to store header parameters
List<NameValuePair> urlParameters = new ArrayList<NameValuePair>(); //ArrayList to store URL parameters
urlParameters.add(new BasicNameValuePair("query","{\"terms\":[{\"type\":\"totango_user_scope\",\"is_one_of\":[\"mobile+testme@totango.com\"]}],\"group_fields\":[{\"type\":\"health\"}]}"));
headers.add(new BasicNameValuePair("app-token", "1a1c626e8cdca0a80ae61b73ee0a1909941ab3d7mobile+testme@totango.com"));
headers.add(new BasicNameValuePair("Accept", "application/json, text/javascript, */*; q=0.01"));
headers.add(new BasicNameValuePair("X-Requested-With", "XMLHttpRequest"));
httpPost.setEntity(new UrlEncodedFormEntity(urlParameters));
for (NameValuePair h : headers)
{
httpPost.addHeader(h.getName(), h.getValue());
}
response = httpClient.execute(httpPost);
if (response.getStatusLine().getStatusCode() != 200) {
throw new RuntimeException("Failed : HTTP error code : "
+ response.getStatusLine().getStatusCode());
}
BufferedReader br = new BufferedReader(new InputStreamReader(
(response.getEntity().getContent())));
String output;
System.out.println("Output from Server .... \n");
while ((output = br.readLine()) != null) {
System.out.println(output);
}
} catch (MalformedURLException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
} finally {
try{
response.close();
httpClient.close();
}catch(Exception ex) {
ex.printStackTrace();
}
}
602392714
清零编程群