这可以通过稍微调整链接问题中的逻辑来实现。请注意，由于图形具有许多节点和边缘，并且增加了图形的大小，因此我更改了中心圆的半径值。另外，我更改了接受问题中字典输入的逻辑。在绘制节点时，我在节点上添加了黑色边框，edgecolors=[(0,0,0,1)]因为某些节点是白色或灰白色的，这使它们很难看清。
import networkx
import numpy as np
import matplotlib.pyplot as plt
# Set up graph, adding nodes and edges
RRR = nx.Graph()
RRR.add_nodes_from(nodesWithGroup.keys())
RRR.add_edges_from(edges)
# Create a dictionary mapping color to a list of nodes
nodes_by_color = {}
for k, v in nodesWithGroup.items():
if v not in nodes_by_color:
nodes_by_color[v] = [k]
else:
nodes_by_color[v].append(k)
# Create initial circular layout
pos = nx.circular_layout(RRR)
# Get list of colors
colors = list(nodes_by_color.keys())
# OPTIONAL: shuffle colors list to get a random arrangement of colors
# import random
# random.shuffle(colors)
# Apply logic from linked answer: https://stackoverflow.com/a/55764135/12366110
# Note altered radius value. In addition, we get the value of posx from the colors list.
angs = np.linspace(0, 2*np.pi, 1+len(colors))
repos = []
rad = 13
for ea in angs:
if ea > 0:
repos.append(np.array([rad*np.cos(ea), rad*np.sin(ea)]))
for color, nodes in nodes_by_color.items():
posx = colors.index(color)
for node in nodes:
pos[node] += repos[posx]
# Plot graph
plt.figure(figsize=(20,20))
for color, nodes in nodes_by_color.items():
nx.draw_networkx_nodes(RRR, pos=pos, nodelist=nodes, node_color=color, edgecolors=[(0,0,0,1)])
nx.draw_networkx_edges(RRR, pos=pos)
plt.show()
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