我个人不会那样做。一种更没有技巧的解决方案是先根据您的数据构建字典，然后将其整体传递给函数**kwargs。例如（这不是最优雅的方法，但这只是说明性的）：
import re
remove_non_digits = re.compile(r'[^\d.]+')
inputList = ["a='0.015in' lPrime='0.292' offX='45um' offY='75um' sPrime='0.393' twistLength='0'",
"a='0.015in' lPrime='0.292' offX='60um' offY='75um' sPrime='0.393' twistLength='0'",
"a='0.015in' lPrime='0.292' offX='75um' offY='75um' sPrime='0.393' twistLength='0'", '']
#remove empty strings
flag = True
while flag:
try:
inputList.remove('')
except ValueError:
flag=False
outputList = []
for varString in inputList:
varStringList = varString.split()
varDict = {}
for aVar in varStringList:
varList = aVar.split('=')
varDict[varList[0]] = varList[1]
outputList.append(varDict)
for aDict in outputList:
for aKey in aDict:
aDict[aKey] = float(remove_non_digits.sub('', aDict[aKey]))
print outputList
打印：
[{'a': 0.014999999999999999, 'offY': 75.0, 'offX': 45.0, 'twistLength': 0.0, 'lPrime': 0.29199999999999998, 'sPrime': 0.39300000000000002}, {'a': 0.014999999999999999, 'offY': 75.0, 'offX': 60.0, 'twistLength': 0.0, 'lPrime': 0.29199999999999998, 'sPrime': 0.39300000000000002}, {'a': 0.014999999999999999, 'offY': 75.0, 'offX': 75.0, 'twistLength': 0.0, 'lPrime': 0.29199999999999998, 'sPrime': 0.39300000000000002}]
这似乎正是您想要的。
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