这个正则表达式应该为您工作 \s+(?=[^()]*(?:\(|$))
result = re.split(r"\s+(?=[^()]*(?:\(|$))", subject)
说明
r"""
\s # Match a single character that is a “whitespace character” (spaces, tabs, and line breaks)
+ # Between one and unlimited times, as many times as possible, giving back as needed (greedy)
(?= # Assert that the regex below can be matched, starting at this position (positive lookahead)
[^()] # Match a single character NOT present in the list “()”
* # Between zero and unlimited times, as many times as possible, giving back as needed (greedy)
(?: # Match the regular expression below
# Match either the regular expression below (attempting the next alternative only if this one fails)
\( # Match the character “(” literally
| # Or match regular expression number 2 below (the entire group fails if this one fails to match)
$ # Assert position at the end of a line (at the end of the string or before a line break character)
)
)
"""
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